Alex doesn't like boredom. That's why whenever he gets bored, he comes up with games. One long winter evening he came up with a game and decided to play it.

Given a sequence a consisting of n integers. The player can make several steps. In a single step he can choose an element of the sequence (let's denote it ak) and delete it, at that all elements equal to ak + 1 and ak - 1 also must be deleted from the sequence. That step brings ak points to the player.

Alex is a perfectionist, so he decided to get as many points as possible. Help him.

Input

The first line contains integer n (1 ≤ n ≤ 105) that shows how many numbers are in Alex's sequence.

The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 105).

Output

Print a single integer — the maximum number of points that Alex can earn.

Examples

input

2 1 2

output

2

input

3 1 2 3

output

4

input

9 1 2 1 3 2 2 2 2 3

output

10

Note

Consider the third test example. At first step we need to choose any element equal to 2. After that step our sequence looks like this [2, 2, 2, 2]. Then we do 4 steps, on each step we choose any element equals to 2. In total we earn 10 points.

 题意：

　　每次从n个数中选中数值为A_k将其删去，并将值为A_k-1的数和值为A_k+1的数全部删去，得到A_k的分数。问最大可获得的分数。

题解：

　　DP一下就好了。

 

#include
           
            #include
            
             #include
             
              using namespace std;const int maxn=1e5+5;long long cnt[maxn],dp[maxn];int main(){    int n;    while(cin>>n)    {        memset(cnt,0,sizeof(cnt));        for(int i=0;i
              
               >x;            cnt[x]++;        }        dp[0]=0,dp[1]=cnt[1];        long long ans=0;        for(int i=2;i